# Plzz solve this Q.5.25 The rate constant of a first order reaction at 25$°$C is 0.24 ${s}^{-1}$. If the energy of activation of the reaction is 88 kJ $mo{l}^{-1}$, at what temperature would this reaction have rate constant of ? (283.7 K)

Dear student,

According to Arrhenius equation :
K1 = 0.24 s-1 and T1 = 298 K
K2  = 4 $×$10-2 s-1   T2 = ?  Ea = 88 kj/mol = 88000 j /mol
Now on putting the values ;
0.77815    =   4596.02
0.000169        =
T2  =283.7 K
Regards

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