Plzz someone solve this

Plzz someone solve this Cli) 4k

By the way, your question's answer

a) In a series circuit, the same current passes through the resistors, so you can take it to be a constant. Power is hence given by:

P = (I^2)R

I in the circuit = 6/(2+1) = 2 A

So power dissipated in 2 ohm resistor = (2^2).2 = 8 Watts.

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b) Potential difference is constant in a parallel circuit. Hence power dissipated across the 2 ohm resistor is directly given as:

(V^2)/R = (4^2)/2 = 8 Watts.

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An interesting observation might be that power dissipated in a parallel circuit does not depend on the resistor connected in parallel, while in a series circuit, as current flow is determined by all the resistors, power dissipation is dependent on the other resistors in the circuit.
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Wht non sense u r talking here!!
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Sneha, Please speak up yaar, who was that?
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That's your answer

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About what nonsense are u talking about
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ahem thi s is not a social networking site so control ur emotions
 
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