Plzz..tell 13 to 19 tomorrow is test...... Plzzz. ...I want them plz.....com

Plzz..tell 13 to 19 tomorrow is test...... Plzzz. ...I want them plz.....com 16 13 14 15 (i) Given - Hint. (ii) Given expression z - 11 each of the as 19 Evaluate the following by using (979B - (21)2 "FACTORISATION OF TRINOMIALS we kam fmtorisabt.m •Bilt

13) 2x4 - 32   # first step take common factors out
=2(x4 - 16)   
=2((x2)2 -42) # a2 - b2 = (a+b)(a-b) a = x2 b = 4
=2(x2 - 42 )(x2 +4)   # a2 - b2 = (a+b)(a-b) a = x b = 2
=2(x2 +4) (x +2)(x-2)   


13 ii) a2(b+c) - (b+c)3  
=(b+c)( a2 - (b+c)2  )
=(b+c)(a2 - ( b2 +a2  +2bc)  )
=(b+c)(a2 - b2 - ​c- 2bc)
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14 i) (a+b)3 - a - b 
=  (a+b)(a2 +b2 - ab) -(a+b)
=(a+b)( a2 +b2 - ab -1)

14 ii) x2 -2xy + y2 -a2 -b2 -2ab
=(x-y)2 - (a+b)
=(x-y +a +b)( x -y -a -b)
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15 i) (a2 - b2)(c2 - d2) - 4abcd
=a2c2 - a2d2 - b2c+ b2d- 4abcd
=a2c2  + b2d- 2abcd  - a2d2 - b2c- 2abcd  
=(ac -bd)2 -(ad +bc)2 # a2c2  + b2d- 2abcd = (ac -bd)2  and - a2d2 - b2c- 2abcd   =  -(ad +bc)2
=(ac -bd + ad + bc)(ac -bd -ad -bc)    # apply x2 -y2 = (x-y)(x+y)

 
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16i ) x2 + 1/x2 -11 
=x2 + 1/x2 -2 -9
= (x)2 + (1/x)2 -2(x)(1/x) -  (3)2  
=(x -1/x)2 -  (3)2  
=(x - 1/x +3)(x -1/x -3)

16 ii) x4 +5x2 +9
=(x2)2 + 2(3)(x2) - x2 +(3)2   
=(x2)2 + 2(3)(x2)  +(3)2  - x2 +
=(x2 +3)2 - (x)2 
=(x2 +3 +x)(​x2 +3 -x)
 
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17 i) a4 + b4 -7a2b2  
=(a2)2 +(b2)2 +2a2b- 9a2b2   # Split -7a2b2  to 2a2b- 9a2b
=( a + b2) - (3ab)2   # ( a + b2) = (a2)2 +(b2)2 +2a2b2
=( a + b2  +3ab)( a + b2  - 3ab)

ii)x4 -14x2 +1
=x4 +2x2  -16x2 +1 # Split -14x2  to 2x2 - 16x 
=x4 +2x2 +1 -16x2 
=(x2)2 +(1)2 +2(x2)(1) -  (4x)2  
=(x2 +1)2 - (4x)2   
=(x2 +1 +4x)(x2 +1 - 4x)
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