PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
By applying Pythagoras theorem in ΔPQR,
(PQ)2 + (PR)2 = (RQ)2
(10)2 + (24)2 = RQ2
100 + 576 = (QR)2
676 = (QR)2
QR = 26 cm
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
By applying Pythagoras theorem in ΔPQR,
(PQ)2 + (PR)2 = (RQ)2
(10)2 + (24)2 = RQ2
100 + 576 = (QR)2
676 = (QR)2
QR = 26 cm