PQRS is a parallelogram. A, B, C and D are the mid points of sides PQ, QR, RS and PS respectively. If area of triangle DAC is equal to 10cm2. Find the area of triangle ABC.



We have PQRS as the parallelogram, in which A, B, C and D are the mid points of the sides PQ, QR, RS and SP.
Join PR and AC.
Since A and B are the mid points of the sides PQ and QR in ∆ PQR, so,
AB  PR and AB = 12 PR    mid point theorem  ......1

Since D and C are the mid points of the sides SP and SR in  SPR, thenDC  PR   and DC = 12PR    mid point theorem    ......2From 1 and 2, we getAB  DC  and AB = DCIn quad. ABCD , we haveAB  DC  and AB = DCquad. ABCD  is a parallelogram Since in a quadrilateral, if a pair of opposite sides is equal and parallel, then quadrilateral is a ||gm.Since AC is the diagonal of ||gm ABCD , so,arADC = arABC diagonals of ||gm divides it into 2 's of equal areasarABC = 10 cm2    , as arADC = 10 cm2
 

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Triangle ADC lies in between same parallel lines and have coman base AC

Therefore Ar(ADC) = 1/2Ar(DACS)

Similarly , Ar(ACB) = 1/2Ar(AQRC)

since A,C are mid points DACR = AQRC -eq1

Ar(ACB) = 1/2Ar(DACR) (from eq1)

Ar(ACB) =Ar(ABC)

10cm2 =10cm2

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