Practical Geometry of 7th class

Practical Geometry of 7th class 2. Construct an angle QPR at P equal to ZPQB in side) of ZPQB in opposite side (alterna09de) of ZPQB . 9. Extend PR on both sides. Then the line PR is the required linf parallel to the given line AB through P. 1. Draw a line AB. Make a point Q outside it- Th a pair of compasses. Method T i p If Interior alternate two lines Intersected equals then each other Q construct a line 2. Draw an angle POQ, with ZO = 600. Through P, truct a line parallel to using a'*é' pair of compasses. 3. Draw a line PQ. Take a point R on it between P and Q make an angle ZTRQ : T draw a line parallel to line PQ A triangle can be constructed if three of its sides te shape, if any of the following three *2des of the triangle are given (SSS and the included angle are given] nd two angles are given(ASA tri three angles are known. But.i itions are fulfilled : gle construction). AS triangle construction). construction).

Dear student,
The solution to your 1st query has been provided below:
 

The following steps are used to solve the question:

Step 1: Draw line AB of any length. Take point P on AB.
Step 2: Mark point Q outside the line at a convenient distance. Join PQ.
Step 3: With P as the center, and any convenient length as radius, draw an arc to cut PQ at E and AB at D.
Step 4: Without altering the compass, taking Q as the center, draw an arc FG to cut PQ at H.
Step 5: Now, measure length ED and with the same radius and H as the center, cut the arc FG at I.
Step 6: Join QI. Extend the line and name it RS.
Step 7: RS is the required line which is parallel to AB.

PQ is the required line which is parallel to AB.

Hope this information will clear your doubts about the topic.
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