Practical Geometry of 7th class

Practical Geometry of 7th class 2. Construct an angle QPR at P equal to ZPQB in side) of ZPQB in opposite side (alterna09de) of ZPQB . 9. Extend PR on both sides. Then the line PR is the required linf parallel to the given line AB through P. 1. Draw a line AB. Make a point Q outside it- Th a pair of compasses. Method T i p If Interior alternate two lines Intersected equals then each other Q construct a line 2. Draw an angle POQ, with ZO = 600. Through P, truct a line parallel to using a'*é' pair of compasses. 3. Draw a line PQ. Take a point R on it between P and Q make an angle ZTRQ : T draw a line parallel to line PQ A triangle can be constructed if three of its sides te shape, if any of the following three *2des of the triangle are given (SSS and the included angle are given] nd two angles are given(ASA tri three angles are known. But.i itions are fulfilled : gle construction). AS triangle construction). construction).

Dear student,
The solution to your 1st query has been provided below:

The following steps are used to solve the question:

Step 1: Draw line AB of any length. Take point P on AB.
Step 2: Mark point Q outside the line at a convenient distance. Join PQ.
Step 3: With P as the center, and any convenient length as radius, draw an arc to cut PQ at E and AB at D.
Step 4: Without altering the compass, taking Q as the center, draw an arc FG to cut PQ at H.
Step 5: Now, measure length ED and with the same radius and H as the center, cut the arc FG at I.
Step 6: Join QI. Extend the line and name it RS.
Step 7: RS is the required line which is parallel to AB.

PQ is the required line which is parallel to AB.

Hope this information will clear your doubts about the topic.
For remaining queries, we request you to post them in separate threads to have rapid
assistance from our experts.



  • 0
Do it yourself !!!!!
  • 0
What are you looking for?