Predict whether F2 and Na will react with one another. Give reason(E0(F2/F-)=+2.87V and E0(Na+/Na)=-2.71V)

Na → Na⁺ + e^- ​
F^- + 2e- → ​F₂ ​
E^o_cell = E^o_red - E^o_oxid
E^o_cell = ​2.87 V + 2.71 V = 5.58 V
Since the emf of the cell is positive, the reaction is spontaneous and these two will react with each other.