Principle=10752, Rate%=12.5%, Time=3years then what is the compound interest

Dear Student

Given

Principle (P) = 10752 /-

Rate of Interest ( R) = 12.5 %

Time (n) = 3 Years

We know that

Amount (A) = $P {\left(1 +\frac{R}{100}\right)}^n$

$$\begin{gathered} =>A = 10752 {\left(1 +\frac{12.5}{100}\right)}^3 \\ =>A = 10752 {\left(\frac{112.5}{100}\right)}^3 \\ =>A = 10752 \times \frac{112.5}{100} \times \frac{112.5}{100} \times \frac{112.5}{100} \\ =>A = 10752 \times \frac{1125}{1000} \times \frac{1125}{1000} \times \frac{1125}{1000} \\ => A = 10752 \times \frac{45}{40} \times \frac{45}{40} \times \frac{45}{40} \\ => A = 10752 \times \frac{9}{8} \times \frac{9}{8} \times \frac{9}{8} \\ => A = 10752 \times \frac{729}{512} \\ => A =21 \times 729 \\ => A = 15309 \\ Therefore, \\ Compound Interest = Amount - Principle \\ = 15309 -10752 \\ = 4557 \\ Regards \end{gathered}$$