Projectile motion:

Q. A particle of mass m is thrown horizontally from point P, as shown in the figure, with speed 5 m/s. It strikes an inclined plane perpendicularly as shown. The inclination of the plane is 30o with the horizontal. Then, the height h shown in the figure is (Take g= 10 m/s2)

(A) 3.75m          ​(B) 5.0m
(C) 4.75m      ​  ​      (D) 0.417


Dear Student,let the speed at which it hit is vthen vsin30=5v=10 m/sfrom energy conservation .m*522=mgh+m*102212.5=10h+50h=37.510=3.75 m option Regards

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