Prove 2220^{2n} ^{+1}+2003^{2n+1}is divisible by 4005,n *belongs to *N

Let P(n) be the statement given by:

P(n) = 2220^{2n} ^{+1}+2003^{2n+1}

In order to prove P(n) is divisible by 4005, we will first verify P(1) as:

P(1) = 2220^{2(1)} ^{+1}+2003^{2(1)+1}

⇒ P(1) = 2220^{3 }+ 2003^{3}

⇒ P(1) = 10941048000^{ }+ 8036054027 = 18977102027 which is not completely divisible by 4005.

Hence, your query appears to be incorrect. Please recheck it.

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