Prove : asinA - bsinB = csin(A - B) Share with your friends Share 9 Anuradha Sharma answered this As we know from sine rule that , sinAa=sinBb=sinCc=k saySo sinA = ak and sinB= bk and sinC= ckand we also know from cos formula that , cos A= b2+c2-a22bc and cos B =a2+c2-b22ac Now taking LHS we get, asinA-bsinB= a×ak-b×bk= k a2-b2now taking RHS we get, csinA-B= csinAcosB-cosAsinB= caka2+c2-b22ac-b2+c2-a22bcbk=k a2-b2Hence RHS = LHS . 16 View Full Answer
