prove by method of vectors that in a tri angle a/sinA=b/sinB=c/sinC - Maths - Vector Algebra

Question

prove by method of vectors that in a tri angle
a/sinA=b/sinB=c/sinC

Hari · Answer

Let a,b and c
be three sides of a triangle and let angles opposite to these sides
be A,B and C respectively We know area of this triangle is = 0 5
|a x b|= 0 5 |b
x c|= 0 5 |c x
a| => abSinC = bcSinA=caSinB=>a/SinA =
b/SinB = c/SinC

prove by method of vectors that in a tri angle a/sinA=b/sinB=c/sinC.