prove (sin3A-cos3A)/(sinA+cosA) + sinAcosA = 1 Share with your friends Share 2 Manbar Singh answered this LHS = sin3A + cos3Asin A + cos A + sin A . cos A= sin A + cos Asin2A + cos2A - sin A . cos Asin A + cos A+ sin A . cos A=sin2A + cos2A - sin A . cos A + sin A . cos A=sin2A + cos2A=1=RHS 2 View Full Answer Dikshant answered this GKJ -6
