Prove that (1-sin2A)*sec2A = 1

Hey Frnd here is your answer:

(1- sin²A) * sec²A =1

== Taking LHS (1- sin²A) * Sec²A

== We know that 1- sin²A= Cos²A

== Now,

== (cos²A)* Sec²A

== cos²A * 1/ Cos²A { We know that sec²A = 1/ Cos²A }

== 1*1

== 1

LHS= RHS

Proved.

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