prove that 2 (cos² 45 + tan² 60) - 6 (sin² 45 + tan² 30) = 6 - Maths - Introduction to Trigonometry

Question

prove that 2 (cos² 45 + tan² 60) - 6 (sin² 45 +
tan² 30) = 6

Anushka Agrawal · Answer

2[(1/21/2)2+(31/2)2 ] -
6[(1/21/2)2 +
(1/31/2)2]
=2[1/2+3] - 6[1/2+1/3]
= 2[7/2] - 6[5/6]
= 7 - 5
=2
which is not equal plz recheck ur question