Prove that a.(b*c) = (a*b).c , where a,b,c, are any arbitrary vectors and * denotes cross product.

Let a=a1i+a2j+a3kb=b1i+b2j+b3kc=c1i+c2j+c3kb×c=b1c2k-b1c3j-b2c1k+b2c3i+b3c1j-b3c2ib×c=b2c3-b3c2i+b3c1-b1c3j+b1c2-b2c1ka.b×c=a1b2c3-b3c2+a2b3c1-b1c3+a3b1c2-b2c1     .....1Now,a×b=a1b2k-a1b3j-a2b1k+a2b3i+a3b1j-a3b2ia×b=a2b3-a3b2i+a3b1-a1b3j+a1b2-a2b1ka×b.c=a2b3-a3b2c1+a3b1-a1b3c2+a1b2-a2b1c3a×b.c=a2b3c1-a3b2c1+a3b1c2-a1b3c2+a1b2c3-a2b1c3a×b.c=a1b2c3-a1b3c2+a2b3c1-a2b1c3+a3b1c2-a3b2c1a×b.c=a1b2c3-b3c2+a2b3c1-b1c3+a3b1c2-b2c1     .....2From 1 and 2, we geta.b×c=a×b.cHence, proved.

  • 0
What are you looking for?