prove that (A-B) U (B-A) =(A U B) - (A intersection B)

  • 45

using A-B =A intersection B'

  • -21

Let A={a,b,c} & B={a,b,d}

LHS=> A-B={c}  and B-A={d} 

Thus, (A-B) U (B-A)={c,d}

RHS=>  A U B= {a,b,c,d}

 B = {c,d}

Thus, (A U B) - (A  B) = {c,d}

LHS=RHS

Hope it helps.

  • -17
What are you looking for?