Prove that { Cos(90-Theta) / 1+sin(90-Theta) } + {1+sin(90-Theta) }/ (cos(90-Theta) } =2cosec Theta Share with your friends Share 8 Varun.Rawat answered this LHS = cos90°-θ1 + sin90°-θ + 1 + sin90°-θcos90°-θ=sin θ1 + cos θ + 1 + cos θsin θ=sin2θ + 1+ cos θ2sin 1 + cos θ=sin2θ + 1 +cos2θ + 2 cos θsin 1 + cos θ=sin2θ + cos2θ + 1 + 2 cos θsin 1 + cos θ=1 + 1 + 2 cos θsin 1 + cos θ=21 + cos θsin 1 + cos θ=2sin θ= 2 cosec θ=RHS 50 View Full Answer