Please follow the given link :
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Alternative method:
cot A + cosec A - 1 / cot A - cosec A + 1 = 1 + cos A / sin A
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shriyansh1994 thats during the time of rationalising ,The time of multiplication it seems its 3 times ,we are simplifying it shriyansh1994 observe carefully.One student had asked the same doubt what you asked but I gave the same solution.He was very satisfied with my same solution which I gave to you and he gave me a thumb up .After observing if you are satisfied do give a thumb up and if any more confusion just mention .
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Imad,after rationalising u got
{(cosA- sinA)(cosA+sinA) +(cosA- sinA) +(cosA- sinA) +1} /[(cosA+sinA) – 1][(cosA+sinA) +1]
but how you got the numerator {(cosA- sinA)(cosA+sinA) +(cosA- sinA) +(cosA- sinA) +1} is it like this know?? {(cosA- sinA)(cosA+sinA) +(cosA- sinA) +(cosA+ sinA) +1} ?????
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LHS = (cotA + cosecA - 1)/(cotA - cosec A + 1)
[cotA + cosecA + (cot2A - cosec2A)] / (cotA – cosecA + 1) {because cot2A – cosec2A = -1}
(cotA + cosecA ) + [ (cotA + cosecA) (cotA – cosecA ) ] / (cotA - cosecA + 1)
(cotA + cosecA) (1 + cotA - cosecA) / (cotA - cosecA + 1)
(cotA + cosecA)
cosA / sinA + 1 / sinA
1 + cosA / sinA
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