Prove that EF is parallel to AB and CD in part (iii) using intercept theorum?

Dear student,
I am giving a solution for c first part as your question is not clear and for the remaining parts kindly ask in another thread

We know that the length of the line segment joining the mid-points of two non-parallel sides is half the sum of the lengths of parallel sides.  E and F are mid-points of AD and BC.  EF= 12 (AB+CD)  Now, given that-  AB=6cm  DC=4cm  EF=12 (6+4)=5cm.

Regards

  • 3
c part
  • 0
What are you looking for?