prove that f(x)=1+x+x2+x3+...+xn is equal to 1-xn/1-x Share with your friends Share 0 Rahul Raj answered this dear student the above expression should be 1+x+x2+...+xn=1-xn+11-xwhich is the sum of terms in GPwe can prove by mathematical inductionfor n=11+x=1-x21-x=1+xfor n=n, assuming it is trfor n=n+1LHS=1+x+x2+...+xn+xn+1=1-xn+11-x+xn+1=1-xn+1+xn+1-xn+21-x=1-xn+21-xso true for n+1 also, the above expression is proved regards 1 View Full Answer