# PROVE  that medians of an equilateral triangle are equal Consider an equilateral ΔABC. Let AD, BE and CF be the medians of BC, AC and AB respectively.

We know that in an equilateral Δ, medians are altitudes as well.

Let AB = BC = AC = x [say]

In right ΔABD, by pythagoras theorem, In right ΔBEC,

BC2 = BE2 + CE2 Similarly, we can show that CF = .

Thus, AD = BE = CF.

hence proved

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i didnt understand this pls explain

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Consider an equilateral ΔABC. Let AD, BE and CF be the medians of BC, AC and AB respectively.

We know that in an equilateral Δ, medians are altitudes as well.

Let AB = BC = AC =x[say]

In right ΔABD, by pythagoras theorem,

In right ΔBEC,

BC2= BE2+ CE2

Similarly, we can show that CF =.

Thus, AD = BE = CF.

hence proved

• 1

Consider an equilateral ΔABC. Let AD, BE and CF be the medians of BC, AC and AB respectively.

We know that in an equilateral Δ, medians are altitudes as well.

Let AB = BC = AC =x[say]

In right ΔABD, by pythagoras theorem,

In right ΔBEC,

BC2= BE2+ CE2

Similarly, we can show that CF =.

Thus, AD = BE = CF.

hence proved

Posted byysindhu sri(student), 1 week, 5 days ago
• 3
Please elaborate a bit I don't understand
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