Prove that sec^2x+cosec^2x>=4 Share with your friends Share 0 Ferdie answered this Sec^2x+Cosec^2x= 1/cos^2x + 1/sin^2x = (cos^2x+sin^2x) / cos^2x sin^2x = 1 / cos^2x sin^2x = 4 / sin^2 2x 4 / sin^2 2x >=4 0 View Full Answer