Prove that sin 58/ cos 32=cos(90-58)/cos 32= cos 32/sin 58=1 Share with your friends Share 0 Neha Sethi answered this Dear student Consider, sin58°cos32°=cos90°-58°cos32° sinx=cos90°-x=cos32°cos32°=1Now consider, cos90°-58°cos32°=cos32°cos32°=1Now consider, cos32°sin58°=sin90°-32°sin58° cosx=sin90°-x=sin58°sin58°=1So, sin58°cos32°=cos90°-58°cos32°=cos32°sin58°=1Hence Proved. Regards 0 View Full Answer
