Prove that sin inverse x= cot inverse root1-x square/x

Dear student
Consider  RHScot-11-x2xPut x=sinA A=sin-1x=cot-11-sin2AsinA=cot-1cos2AsinA=cot-1cosAsinA=cot-1cotA=A=sin-1x=LHSNote:sin2x+cos2x=1
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