prove that :tan inverse [ 3sin(2x)/(5+3cos(2x)) ]+ tan inverse [ (1/4)tanx ] = x

LHS =tan-1(3sin2x5+3cos2x) + tan-1(14tanx)= tan-1(3×2tanx1+tan2x5+3×(1-tan2x1+tan2x)) +tan-1(14tanx)=tan-1(6tanx8+2tan2x) + tan-1(14tanx)As (tan-1x +tan-1y = tan-1x+y1-xy)So tan-1(6tanx8+2tan2x) + tan-1(14tanx) = tan-1(6tanx8+2tan2x+14tanx1-6tanx8+2tan2x×14tanx)= tan-1(tanx) = x = RHS

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