prove that tan+sec-1/tan-sec+1 =1+sin/cos

  • -1

multiply LHS by cos /cos to get(sin+1-cos) / (sin-1+cos)multiply again by cos/cos to get(sin.cos+cos-cos^2) / cos(sin-1+cos)= ( cos(1+sin) - (1-sin^2) ) / cos(sin-1+cos)= ( cos(1+sin) - (1+sin)(1-sin) ) / cos(sin-1+cos)= ( (1+sin)(cos-1+sin) ) / cos(sin-1+cos)= (1+sin)/cos

  • -11
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