prove that the energy remains constant in case of a freely falling body....

 

  A  at point A KE+ PE = mgh + 0= mgh

  h  at point B KE +PE = 0+1/2 mv2

  =  0+ 1/2 m * 2gh  ( v2 = u+ 2as0

  =mgh  u =0  , v2 = 2as = 2gh)

 

 

 

  • -6
What are you looking for?