Prove that the hybridisation of Be is sp in BeCl ₂ .

basically ; 
in Be there are 4 electrons 1s² and 2s²
so during hybridisation the 2s² electrons get exited to 2s¹ , 2p_x^1. 2p_y⁰  2p_z0
as there are unpaired electrons in 2s¹ and 2p_​x¹ the cl atoms will combine with these orbitas to form BeCl₂
so now there ar two sp hybrib orbitals and hence we can say that hybrid of be in BeCl₂ is sp .