Prove that the lengths of tangents drawn from an external point to a circle are equal. Using the above, prove that PP’ = QQ’ in the figure.
P'A=P'Q tangents from external point ....(1)
also,
AP=AQ tangents from external point....(2)
subtracting(1)and (2),
AP-AP'=AQ-AQ'
Therefore, PP'=QQ'
also,
AP=AQ tangents from external point....(2)
subtracting(1)and (2),
AP-AP'=AQ-AQ'
Therefore, PP'=QQ'