prove that the medians bisecting the equal sides of an isosceles triangle are also equal
now, here we have to prove that BD = CE when AB = AC. ( where BD and CE are the medians)
now, in ΔEBC and ΔDCB,
AB = AC
=> 1/2 AB = 1/2 BC
=> BE = CD ( BE = CD = 1/2AB = 1/2BC as BD and CE are the medians of a triangle) ....... (1)
now, BC = CB
and, ∠EBC = ∠DCB
hence, by SAS congruency,
ΔEBC ≅ ΔDCB
now, by congruent parts of congruent triangles property,
BD = CE
so, we have proved that medians bisecting the equal sides of an isosceles triangle are also equal.
hope it helps!!
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