PROVE THAT the sum of the angles of a triangle is 180 degree

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Proof of the angle sum theorem


Angle sum theorem: The angle measures in any triangles add up to 180 degrees

Key concept: Alternate interior angles are equal. We will accept this fact without a proof



The figure above shows two pairs of alternate interior angles.

For the pair in red, angle 1 = angle 2. For the pair in blue, angle 3 = angle 4

Now, take a close look at the figure below. I claim that angle x is equal to 85 degrees so the sum is 180 degrees



To see why this is so, draw a line parallel to AC at vertex B



Angle a = 65 degrees because it alternates with the angle inside the triangle that measures 65 degrees

Angle b = 30 degrees because it alternates with the angle inside the triangle that measures 30 degrees

Looking at the figure again, it is easy to see why angle x is 85.

Since the 65 degrees angle, the angle x, and the 30 degrees angle make a straight line together, the sum must be 180 degrees

Since, 65 + angle x + 30 = 180, angle x must be 85

This is not a proof yet. This just shows that it works for one specific example

Proof of the angle sum theorem:

Start with the following triangle with arbitrary values for the angles:



Since angle a, angle b, and angle c make a straight line,

angle a + angle b + angle c = 180 degrees

Since alternate interior angles are equal, angle a = angle x and angle b = angle y

Therefore, angle x + angle y + angle c = 180 degrees

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here is the picture.

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Consider a triangle PQR and 1, 2 and 3 are the angles of ΔPQR (figure shown below). We need to prove that 1 + 2 + 3 = 180.

XPY is a line.∴4 + 1 + 5 = 180 (1)But XPY || QR and PQ, PR are transversals.So, 4 = 2 and 5 = 3 (Pairs of alternate angles)Substituting 4 and 5 in (1), we get2 + 1 + 3 = 180∴1 + 2 + 3 = 180
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Steps
  1. 1Draw a line PQ through the vertex A and parallel to the side BC of a triangle ABC. Ad
  2. 2Now, angle PAB + angle BAC + angle CAQ = 180 degrees (as PQ is a straight line). Call this as Equation 1.
  3. 3Angle PAB = angle ABC (as PQ AND BC parallel lines and AB is transversal;alternate interior angles). Call this as Equation 2
  4. 4Angle CAQ = angle ACB (as PQ AND BC parallel lines and AC is transversal;alternate interior angles). Call this as Equation 3
  5. 5Substitute angle PAB and angle CAQ in Equation 1 by angle ABC and angle ACB (as found in Equation 2 and Equation 3) respectively.
    • Thus we get, Angle ABC + angle BAC + angle ACB = 180 degrees.
    • In other words, in the triangle ABC, angle B + angle A + angle C = 180 degrees. Thus the sum of all the angles of a triangle is 180 degrees
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