Login

prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides

Here is the link for the answer to your query:

https://www.meritnation.com/ask-answer/question/show-that-the-sum-of-the-sq-of-the-four-sides-of-a-parallel/triangles/5795648

  • 1
View Full Answer

here DE and CF are the perpendiculars drawnIn triangle BCFb2= p2+ x2 (1)In triangle ACFd12= p2+ (a+x)2 (2)Subtract (1) from (2)d12- b2= a2+ 2axIn triangle DAEb2= p2+ x2in triangle DEBd22= p2+ (a-x)2d22= a2+ b2-2axthus we get d12+ d22= 2(a2+ b2) = Sum of the squares of the sides

  • -16
What are you looking for?