prove that the term independent of x in the expansion of (x+1/x)^2n is 1.3.5......(2n-1)/n! .2^n

Since there are 2n+1 term so by looking at the expansionx+1x2n we can say that term independent of x will be middle termSo in x+1x2n the middle term will be = 2nCn=2n!n!×n!=1.2.3.4...n.n+1...2nn!×n!=1.3.5......2n-12.4.6....2nn!×n!=1.3.5......2n-1×2n1.2.3.4.....nn!×n!=1.3.5......2n-1×2nn!n!×n!=1.3.5......2n-1×2nn!=

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