Prove that the vectors A=6i+9j-12k and B=2i+3j-4k are parallel. Share with your friends Share 10 Aditi answered this Two vectors are said to be parallel when their cross product is zero.So,A⇀×B⇀ =6i+9j-12k × 2i+3j-4k = ijk69-1223-4 =(-36 +36) i^ --24 + 24 j^ + 18-18 k^ = 0So as their cross product is zero so we can call them as parallel vectors. 32 View Full Answer Rohan Ganguly answered this The slope of both the vectors are equal so they are parallel.Slope = tanΘtanΘ = y/xtan Θ = 3/2 for both the vectors. 2
