prove that there is no term involving x^5 int he expansion of (2x^2-3/x)^11
let's do it by contradiction :
let r+1th the term contain X5 in the expansion of (2x2 -3/x)11
so Tr+1 = 11cr(2x2)11-r (-3/x)r
(now remove the coefficients and focus on the variable 'x' and equate it with x5 since we are assuming this term to contain x5)
x22-2r-r = x5
22-3r = 5 (cancel out x)
r = 17/3
which is not possible because n belongs to whole numbers only .
HENCE PROOVED !