prove that there is no term involving x^5 int he expansion of (2x^2-3/x)^11

let's do it by contradiction :

let r+1th the term contain X5 in the expansion of (2x2 -3/x)11

so Tr+1 = 11cr(2x2)11-r (-3/x)r

(now remove the coefficients and focus on the variable 'x' and equate it with x5 since we are assuming this term to contain x5)

x22-2r-r = x5

22-3r = 5 (cancel out x)

r = 17/3

which is not possible because n belongs to whole numbers only .

HENCE PROOVED !

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