prove that 1 + sino/1 - sino = (seco + tano)2 Share with your friends Share 0 Manbar Singh answered this LHS = 1 + sin θ1 - sin θ=1 + sin θ1 - sin θ × 1 + sin θ1 + sin θ=1+sin θ1+sin θ1-sin θ1+sin θ=1+sin θ212 - sin θ2=1 + sin2θ + 2 sin θ1 - sin2θ=1 + sin2θ + 2 sin θcos2θ=1cos2θ + sin2θcos2θ + 2 × 1cos θ × sin θcos θ=sec2θ + tan2θ + 2 sec θ tan θ=sec θ + tan θ2=RHS 1 View Full Answer Error Who Dahellyatrynacontact... answered this Take LHS:Rationalise: 1+sin / 1-sin * 1+sin/ 1+sinnow you get = (1=sin)^2 / 1 - sin^2 [^ means power]now take RHS:convert sec to 1/ cos and tan to sin/cos= (sec+tan)^2 = (1/cos + sin /cos)^2=(1+sin / cos)^2=(1+sin)^2 / 1-sin^2=RHS[cos^2 = 1 - sin^2]{please igore theta for now} 1
