Prove the following:
1. log 9/5+log 15/9-log 3/2=log 2
2. 2 log 3/7+log 49/9=0
3. logb*ca=log​ba/1+logbc

Dear Student,
Please find below the solution to the asked query:

3. L.H.S= logbcaUse base change formula  logpq=logrqlogrpL.H.S.=logbalogbbc=logbalogbb+logbc As logm·n=logm+logn=logba1+logbc=R.H.S. Hence Proved

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log 9/5=log 9 -log 5
log 15/9= log 15 -log 9
log 3/2= log 3- log 2
 
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