prove the following by mathematical induction:- 102N-1+1 IS DIVISIBLE BY 11

Hi!

Let p(n) be 102n-1+1 =11p

p(1) = 10+1 = 11 which is divisible by 11

Let p(k) be true.

p(k) = 102k-1+1 = 11m

p(k+1) = 102(k+1) - 1+1

=102k+2-1+1

=102k-1.102+1

=11m . 102

which is a multiple of 11.

Hence by principle of mathematical induction, p(n) is true for all n∈N.

  • -2

Hi!

Let p(n) be 102n-1+1 =11p

p(1) = 10+1 = 11 which is divisible by 11

Let p(k) be true.

p(k) = 102k-1+1 = 11m

p(k+1) = 102(k+1) - 1+1

=102k+2-1+1

=102k-1.102+1

=11m . 102

which is a multiple of 11.

Hence by principle of mathematical induction, p(n) is true for all n ∈ N

  • 14
can i have a explained ans
  • 4
What are you looking for?