Prove the Identities?
( Sec8A-1)/( Sec4A-1)=Tan8A/Tan2A
(sec 8A - 1) / (Sec 4A - 1) Taking LCM we get
[(1 - cos 8A) * cos 4A] / [(1 - cos 4A) * cos 8A]
= (2sin24A.cos 4A) / (2sin22A.cos 8A) [ (1 - cos 8A) = 2sin24A and (1 - cos 4A) = 2sin22A]
= (2sin 4A.cos 4A.sin 4A) / (2sin 2A.sin 2A.cos8A)
= (sin 8A.2sin 2A.cos 2A) / (2sin 2A.sin 2A.cos 8A) [2sin4A.cos4A = sin8A and sin4A = 2sin2A.cos2A]
= (sin 8A) / (cos 8A) * (cos 4A) / (sin 4A)
= (tan 8A) / (tan 2A)
Hence Proved.