~~Put the equation 12y=5x+65 in the form of xcosθ+ysinθ=p and indicate clearly in a rough diagram the position of the straight line and the meaning of the constant θ and p.

Dear Student,
Let me explain the normal for a line:



So here 5x-12y=-65Divide both side 52+122= 13513x-1213y=-5comparing with xcosα+ysinα= p p = -5 and cosα=513, sinα=-1213tanα=-125 so= tan-1-125p= -5
Regards

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