Q 1 AB is the diameter of a circle, centre O C is the point on circumference such - Maths - Areas Related to Circles

Question

Q 1 AB is the diameter of a circle, centre O C is the point on
circumference such that angle COB = x The area of the minor segment
cut off by AC is equal to twice the area of the sector BOC Prove
that:
sinx/2cosx/2 = pi(1/2 - x/120)

Ankush Jain · Accepted Answer

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Q.1 AB is the diameter of a circle, centre O. C is the point on circumference such that angle COB = x. The area of the minor segment cut off by AC is equal to twice the area of the sector BOC. Prove that: sinx/2cosx/2 = pi(1/2 - x/120)

Q.1 AB is the diameter of a circle, centre O. C is the point on circumference such that angle COB = x. The area of the minor segment cut off by AC is equal to twice the area of the sector BOC. Prove that:

sinx/2cosx/2 = pi(1/2 - x/120)