Q.1. The value of r = 0 10 · C r 10 · 3 r · - 2 10 - r is

Dear Student,


using binomial expansion we knowa-bn=r=0nCrn×an-k×-bkcomparing this to the given problem we getr=010Cr10×-210-r×3rhence we gwta=-2 and -b=3a=-2 and b=-3we getr=010Cr10×-210-r×3r=-2--310=3-210=110=1Hence value of r=010Cr10×-210-r×3r=1
Regards,

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