Q.10. A 1 μ F capacitor is connected to a 220 V - 50 Hz a.c. source. Find the virtual value of current through circuit. Find the virtual value of current through circuit. What is the peak value of voltage across the capacitor?

Dear student,
Xc=12πfC
Xc=12×3.14×50×1×10-6Xc =3180ohmsIrms=EXc=2203180=0.069APeak current = 2×IrmsPeak current  = 1.41×0.069Peak current   = 0.097 A

Peak voltage =0.097×3180Peak voltage = 310.2 V

Regards
 

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