Q.10. Find the equation of a circle which passes through the centre of the circle x 2 + y 2 + 8 x + 10 y - 7 = 0 and is concentric with the circle 2 x 2 + 2 y 2 - 8 x - 12 y - 9 = 0 .

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Please find below the solution to the asked query:

2x2+2y2-8x-12y-9=0x2+y2-4x-6y-92=0Centre of circle is 2,3As circle is concentric with x2+y2-4x-6y-92=0, hence centre of required circle is also O2,3Centre of circle x2+y2+8x+10y-7=0 is A-4,-5Required circle passes through A-4,-5Hence radius=OA=2+42+3+52=36+64=10Hence equation is x-22+y-32=102x-22+y-32=100

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