Q.108. Number of gm of oxygen in 32.2 g is
(a) 20.8
(b) 22.4
(c) 2.24
(d) 2.08
Dear student,
The total number of oxygen atoms in this compound is =4+10=14.
The total number of moles of O2 in this compound is =nx14.
The molecular mass of Na2SO4.10H2O=322g/mol
Thus, moles=32.2/322=0.1 moles
Moles of oxygen =0.1x14=1.4 moles
So, weight of oxygen will be = 16x1.4=22.4gm
The correct answer is (b)
Regards
The total number of oxygen atoms in this compound is =4+10=14.
The total number of moles of O2 in this compound is =nx14.
The molecular mass of Na2SO4.10H2O=322g/mol
Thus, moles=32.2/322=0.1 moles
Moles of oxygen =0.1x14=1.4 moles
So, weight of oxygen will be = 16x1.4=22.4gm
The correct answer is (b)
Regards