Q.14. The molecular weight of and are 32 and 28 respectively. At 15 the temperature of 1 g of will be the same as 1 g of in the same bottle at the temperature -
(1) 56
(2) - 15
(3) 13
(4) - 21
Dear student ,
Volume is same.
For oxygen:
Number of moles of 1 g of O2 = Given mass/Molar mass
n = 1/32
PV = nRT
T = 15+ 273 = 288K
PV =
For Nitrogen :
Number of moles of 1 g of N2 = 1/28
PV= nRT
PV=
=
T = 252 K
T = 252-273 = -21oC
Option 4 is correct.
Regards
Volume is same.
For oxygen:
Number of moles of 1 g of O2 = Given mass/Molar mass
n = 1/32
PV = nRT
T = 15+ 273 = 288K
PV =
For Nitrogen :
Number of moles of 1 g of N2 = 1/28
PV= nRT
PV=
=
T = 252 K
T = 252-273 = -21oC
Option 4 is correct.
Regards