Q.2. Sudhakar borrows Rs. 22500 at 10% per annum, compounded annually. If he repays Rs. 11250 at the end of first year and Rs. 12250 at the end of second year, find the amount of loan outstanding against him at the end of third year. Share with your friends Share 5 Neha Sethi answered this Dear student Let the amount of loan outstanding against him at the end of third year=Rs xWhen Sudhakar borrows Rs 22500 at 10% per annum compounded interest.then CI=P1+R100n where P=principal,R=rate of interest,n=timeCI=225001+0.13CI =225001.13If he repays Rs 11250 at the end of first year, and Rs 12250 at the end of second year then,=112501.1+122501.12A.T.Qx+112501.1+122501.12=225001.13⇒x+12375+14822.5=29947.5⇒x+27197.5=29947.5⇒x=2750So, the amount of loan outstanding against him at the end of third year=Rs 2750 Regards -16 View Full Answer