Q.3
Q.3 3. dice are thrown simultaneously, then probability 35 (A) 63 x 3 6 70 63 x 3 6 There are 3 bags A, B & C. Bag A contains 1 Red & 2 Green balls, bag B contains 2 Red & I Green balls and bag C contains only one green ball. One ball is drawn from A & put into bag B then one ball is drawn from B & put into bag C & one is C & put into bag A. When this operation is completed, reen balls, is -

Dear Student,
Please find below the solution to the asked query:

We have 7 dices, hence Total cases = 6^{7} Now we choose 6 out of 7 dices arrange numbers 1 - 6 to them and on 7 th dice, any of 6 numbers can come . Hence Required Probability = \frac{^{7} C_{6} \times 6! \times 6}{6^{7}} = \frac{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \times 6}{6^{7}} = \frac{35 \times 4}{6^{4}} = \frac{70}{6^{3} 3} [Answer]

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