Q.34 Q34. 1 mole of a diatomic gas is contained in a piston. It gains 50.0J of heat and work is done on the surrounding by system is - 100 J. Thus, ( A ) t h e g a s w i l l c o o l b y 2 . 41 ° ( B ) t h e g a s w i l l h e a t b y 2 . 41 ° ( C ) t h e g a s w i l l c o o l b y 3 . 61 ° ( D ) t h e g a s w i l l h e a t b y 3 . 61 ° Share with your friends Share 3 Raveena Sharma answered this The solution is as follows: ∆T = C∆Q = 75R-100+50 = -2.41 The correct option is (a) the gas will cool by 2.410. -4 View Full Answer